perhitungan konsentrasi
Post on 21-Apr-2015
41 Views
Preview:
TRANSCRIPT
TUJUAN :
a = 0.169
b = 0.646
r = 0.9998
FRANZ SEL
y = a + b x
t = 30 >>> 0.479 = 0.169 + 0.646 x
x = 0.479
t = 60 >>> 0.069 = 0.169 + 0.646 x
x = - 0.155
t = 90 >>> 0.045 = 0.169 + 0.646 x
x = -0.192
t = 12 >>> 0.069 = 0.169 + 0.646 x
x = -0.155
Konsentrasi = x x factor pengenceran (10x)
t = 30 >>> 0.479 x 10 = 4.79
t = 60 >>> - 0.155 x 10 = -1.55
KONSENTRASI (PPM) ABSORBAN (AUC)0.5 0.5287 1 0.80652 1.47233 2.1088 4 2.72086 4.03617 4.66428 5.31409 6.0583
MENIT KE- NILAI MPA30 0.47960 0.06990 0.045120 0.069
t = 90 >>> -0.192 x 10 = -1.92
t = 120 >>> -0.155 x 10 = -1.55
FLOW THROGH
MENIT KE- NILAI MPA30 0.66060 0.72090 0.675120 0.215
Y = a +b x
t = 30 >>> 0.660 = 0.169 + 0.646 x
x = 0.76
t = 60 >>> 0.720 = 0.169 + 0.646 x
x = 0.853
t = 90 >>> 0.675 = 0.169 + 0.646 x
x = 0.783
t = 120 >>> 0.215 = 0.169 + 0.646 x
x = 0.071
Konsentrasi = x x factor pengenceran (10x)
t = 30 >>> 0.76 x 10 = 7.6
t = 60 >>> 0.853 x 10 = 8.53
t = 90 >>> 0.783 x 10 = 7.83
t = 120 >>> 0.071 x 10 = 0.71
top related