5. lampiran e102

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LEMBAR PERHITUNGAN

Nama Alat Stripper Outlet Cooler Kode

Fungsi Untuk menurunkan suhu MEA keluaran stripper E-102

Data perancangan:

Fluida pendingin ang digunakan adalah air

Fluida ang akan didinginkan adalah MEA

Untuk !luida panasMEAdan !luida dingin airmaka harga UD" 200 # $00 %tu&hr !t2

F ' Kern(1)*$+(

Alat penukar panas ang digunakan adalahshell and tube exchanger

%e,an panas '+ " 2$$1*$).(0$ %tu&/am

Keterangan MEA Air enis Fluida

a/u alir 'l,&/am+

masuk 'oF+

keluar 'oF+

Fluida panas

1$03$(2)2

2**

14)

Fluida dingin

30)33)($)$3

.2

11.

1( MD 'og Mean emperature Di!!erence+

!luida panas5 F !luida dingin5 F selisih

2** temperatur tinggi 11.(4 143(*14.($0$ temperatur rendah .2(4 **(10$

113(4)$ selisih 6* .1(4)$

2( emperatur 7ata-rata

12

12

&log652 tt

ttLMTD

= " 101(4$$1 F

F" 0()1$

MD " )2(.6

Dibuat Diperiksa Disetujui

22

2*(612

21=

=

tt

TTR

2(0t-t-t

11

12==S

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6( emperatur kalorik5 a " 203(2$2$ oF dan ta " 100(4 oF

F2$2$(0322

14)2**

2

a o21 =

+=

+=

T

F4(0012

4(2.4(11.

2

tta o21 =

+=

+=

t

4( uas 8erpindahan 8anas 'A+

a( Asumsi harga UD" 2*0 %tu&hr !t2(

2

2 1)6(10$3

.614()2((&2*0

&0$(2$$1*$).ft

FxFftjamBtu

jamBtu

tU

A

D

==+

=

untuk luas perpindahan panas 'A+ 9 200 !t25 maka digunakan /enis alat penukar panas shell

and tube heat exchanger'Kern5 1)*$+(

Dipilih diameter luar 'D+ pipa ; in :

a

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Keterangan Nilai

>D 'in+

%a!!le space5 % 'in+

8asses

26(2$

*

1

$( Flo? area 'as+

21)63$(0)63$(0144

*.13$(02$(26

144

=ft

x

inxxin

"x

Bx#x$Da

T

s ===

*( Kecepatan perpindahan massa '@a+

22 (34242(33.0*

1)63$(0

&2)2(1$03$

fthrlb

ft

jamlb

a

%&

s

s ===

3( %ilangan 7enold '7es+

8ada a " 203(2$2$ F

De " 0($$ in " 0(04$.66 !t 'Kern5 1)*$+

" 4(.1$24 l,&!t(hr 'Ba?s51)))+

03$*(340$)4

++(''.1$24(4

++(''342(33.0*+(4$.6(0'

7e2

=

==

hrftlb

fthrlbft

&D aes

.( Dari @am,ar 2.5 Kern didapatkan /C" 4*0 'Fig( 2.5 Kern+

)( 8ada a " 203(2$2$ oF5 nilai p " .(0$10-4%tu&'l,+'F+ dan k " 051$2 %tu&hr !t2 'F&!t+

2)461(0( 6

1

=

'

c

10( 124(44)(((6

1

=

='

c

D

'j

h

e

(

s

)

115 125 16( s" 1 'Giskositas rendah+


24

8/13/2019 5. lampiran E102

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++('+('&'124(44)

2

0 FfthrBtu

h

hs

i)==

#old Fluid : Tube side" #$ %da& MEA

Air se,agai !luida ang dingin dialirkan pada tube sidekarena la/u alirna le,ih

,esar di,andingkan la/u alir MEA( Data desain ang digunakan5 aitu:

Keterangan Nilai

Num,er dan pan/ang '!t+

D dan >D 'in+

%H@5 8itch5 8dan 8asses

*)2 dan 20

0(3$ dan 0(*2

1*5 1$ dan 2$( Flo? area 'at+

( ) ( ) 24404(02144

602(0(420

(144

=(ft

xn

ta!a tt ===

*( Kecepatan perpindahan massa '@t+

( )22 +'11(1*11$.44404(0&$)$3(30)33)

fthrlb

ft

jamlb

a

*&

t

t ===

fps&

+ t 0$660.(3(6*00

==

3( %ilangan 7enold '7ea+

8ada ta " 100(4 F

De " 0(*2 in " 0(0$1**3 !t 'Kern5 1)*$+

" 1(**)46 l,&!t(hr 'Ba?s5 1)))+

( )( )( )

( ) ( )6*(4).3*

**)46(1

11(1*11$.40$1*3(0

7e

2

=

==hrft

lb

fthrlbft

&D tet

10( hi " 1*00 Fig( 2$5 Kern

11( **3(1622==,D

$Dxhh ii)


2$

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%erdasarkan nilai hodan hioang diperoleh dari hasil perhitungan padashell side

dan tube side5 maka:

11( lean Gerall oe!!icient5 Uc:

F!t%tu&hr2334(66$( 2

=+

=

)i)

)i)

hh

hhUc

12( Design Gerall oe!!icient5 UD:

( ) ( )( ) BtuFfthr

UxUcUUcR

D

Dd

200121(0==

PENURUNAN TE'ANAN

1( Untuk 7e " 340$)4()3$*

! " 0(000)$ !t2&in2 'Fig( 2)5 Kern+

2( Num,er o! cross5

2.$3(64(12

1 ==+ B

L!

0(01*3)$s

!t1()6.De

=

=

6(

" 3(3*4$0) psi

1( Untuk 7e " 4).3*(6*2$.

! " 0(0001) !t2&in2 'Fig( 2*5 Kern+

2(1s

!t0(0$1**3De

=

=

" $(1261 psi

6( 6(02 =

2

=g

+


2*

se

sss

sDx

!Df&"

10

2

1022($

+1' +=

t

tt

sDxLnf&"

10

2

1022($=

4(2=2

(4

2

==g

+

s

n"r

psi""" rtT $26(3=+=

8/13/2019 5. lampiran E102

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LEMBAR PERHITUNGAN



Iummar

44)(124111$ h outside 1622(*****3

Uc 66$(23344.*

UD 26.(16.341$

7d calculated 0(00121**2.

7d reJuired 0(001

3(3*4$0)141 alculated D8 3($26144..

10 Allo?a,le D8 10

@am,ar 2( Iketsa Ihell and u,e Ceat Echanger


23

t1" 2.o 2" *4(32$

o

t2" 4.o 1" 160

o

5. lampiran e102

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