tugas remedial quiz
TRANSCRIPT
TUGAS REMEDIAL QUIZ
Nama : Tia Lestari Dewi Yanti
Kelas :1E
1. ∫ x7+¿¿5x2+7x6 dx= 18
x5+53x3+x7 c
2. ∫ x4+¿¿3x4+5x6 dx= 15
x5+35x5+5
7x7
c
3. ∫ x6+¿¿6x2+8x2 dx= 17
x7+x3+83x3
c
4. ∫ x3+¿¿x4+9x3 dx= 14
x4+15x5+ 9
4x4
c
5. ∫ x7+¿¿5x2+7x6 dx= 18
x5+53x3+x7 c
6. ∫ 4
x3+¿ 2x5
+ 6x8dx¿=∫ 4 x−3+2 x−5+6 x−8dx
=4
−2x−2−2
4x−4−6
7x−7+c
7. ∫ 3
x3+¿ 7x4
+ 3x8dx ¿=∫3 x−3+7 x−4+3x−8dx
=3
−2x−2−7
3x−3−3
7x−7+c
8. ∫ 1
x3+¿ 1x4
+ 1x8dx ¿=∫ x−3+x−4+x−8dx
=1
−2x−2−1
3x−3−1
7x−7+c
9. ∫ 1
x3+¿ 4x4
+ 6x8dx ¿=∫ x−3+4 x−4+6 x−8dx
=1
−2x−2−4
3x−3−6
7x−7+c
10. ∫ 1
x3+¿ 4x4
+ 6x8dx ¿=∫ x−3+4 x−4+6 x−8dx
=1
−2x−2−4
3x−3−6
7x−7+c
11. ∫ 2
√ x3+ 32√x3
dx=∫ 2x3
−2+3 x3
−2 dx
= −4 x1
−2−6 x1
−2+c
12. ∫ 3
√ x6+ 42√x7
dx=∫ 3 x6
−2+4 x7
−2 dx
= −64x4
−2−85x5
−2+c
13. ∫ 3
√ x6+ 42√x7
dx=∫ 3 x6
−2+4 x7
−2 dx
= −64x4
−2−85x5
−2+c
14. ∫ 1
√ x6− 1
2√ x7dx=∫ x
6−2−x
7−2 dx
= −24x4
−2 +27x5
−2+c
15. ∫ 8
√ x5− 9
2√ x8dx=∫8 x
5−2−9 x
8−2 dx
= −163x3
−2 +186x6
−2+c
16. ∫sin 4 x .cos5 x dx = 12∫ sin(5+4) x+sin (5−4 ) xdx
=12
∫sin 9x+sin x dx
=−118cos8 x−1
2cos x+c
17. ∫sin 7 x .cos8 xdx = 12∫ sin(8+7)x+sin (8−7 ) xdx
=12
∫sin 15 x+sin x dx
=−130cos15 x−1
2cos x+c
18. ∫sin 3 x .cos 9 xdx = 12∫ sin(9+3)x+sin (9−3 ) x dx
=12
∫sin 12 x+sin 5x dx
=−124cos12 x− 1
10cos5 x+c
19. ∫sin 2 x .cos5 x dx = 12∫ sin(5+2) x+sin (5−2 ) xdx
=12
∫sin 7 x+sin 3 x dx
=−114cos7 x−1
6cos3 x+c
20. ∫sin 6 x .cos9 x dx = 12∫ sin(6+9)x+sin (9−3 ) xdx
=12
∫sin 15 x+sin 6 x dx
=−130cos15 x− 1
12cos6 x+c
21. ∫cos 4 x .cos5 x=12∫ cos (5+4 ) x+¿cos (5−4 ) x dx¿
= 12∫ cos9 x+cos x dx
=118sin 9 x+1
2sin x+c
22. ∫cos 6 x .cos8 x=12∫cos (8+6 ) x+¿cos (8−6 ) xdx ¿
= 12∫ cos14 x+cos 2x dx
=128sin 14 x+ 1
4sin 2x+c
23. ∫cos 3x .cos9 x=12∫cos (9+3 ) x+¿cos (9−3 ) x dx¿
= 12∫ cos12 x+cos6 x dx
=124sin12 x+ 1
12sin 6 x+c
24. ∫cos x .cos8 x=12∫cos (8+1 ) x+¿cos (8−1 ) x dx¿
= 12∫ cos9 x+cos7 x dx
=118sin 9 x+ 1
14sin 7 x+c
25. ∫cos 2x .cos10 x=12∫ cos (10+2 ) x+¿cos (10−2 ) x dx¿
= 12∫ cos12 x+cos8 x dx
=124sin12 x+ 1
16sin 8 x+c