perhitungan panas skripsi

2
Bahan A B C D C2H4 32.0830 -0.014831 0.00024774 -2.3766E-07 C2H4O 30.8270 -0.0076041 0.00032347 -3.2747E-07 O2 29.5260 -0.0088999 0.000038083 -3.2629E-08 CP= A + BT + CT2 + DT3 + ET4 hasil integral= AT + BT2/2 + CT3/3 + DT4/4 + ET5/5 T -225 225 T2/2 -92362.5 92362.5 T3/3 -38864025 38864025 T4/4 -16732990856 16732990856 T5/5 -7.35596E+12 7.35596E+12

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Sheet1BahanABCDECPC2H432.0830-0.0148310.00024774-0.00000023770.0000000001-12002.4785319051C2H4O30.8270-0.00760410.00032347-0.00000032750.000000000114041.0565638711O229.5260-0.00889990.000038083-0.00000003260-6820.5898477153

CP=A + BT + CT2 + DT3 + ET4-18823.0683796204hasil integral=AT + BT2/2 + CT3/3 + DT4/4 + ET5/5T-225225T2/2-92362.592362.5T3/3-3886402538864025T4/4-16732990856.2516732990856.25T5/5-73559601429757355960142975

Sheet2

Sheet3