kfhc tpb reguler zfactor fix
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7/23/2019 Kfhc Tpb Reguler Zfactor Fix
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NAMA KELOMPOK : 1. ANDRI RAHMAT W 1401151
2. ILHAM RIFALDI 1401200
3. VALENTINUS DIMAS 1401194
C1 0.775 16.043 12.43333
C2 0.083 30.070 2.49581
C3 0.021 44.097 0.926037
i-C4 0.006 58.124 0.348744
n-C4 0.002 58.124 0.116248i-C5 0.003 72.151 0.216453
n-C5 0.008 72.151 0.577208
C6 0.001 86.178 0.086178
C7 0.001 100.205 0.100205
N2 0.050 28.013 1.40065
CO2 0.030 44.010 1.3203
H2S 0.020 34.076 0.68152
C1 0.775 16.043 666.4 343.33 266.08075 516.46
C2 0.083 30.070 706.5 549.92 45.64336 58.6395
C3 0.021 44.097 616.0 666.06 13.98726 12.936
i-C4 0.006 58.124 527.9 734.48 4.40688 3.1674
n-C4 0.002 58.124 550.8 765.62 1.53124 1.1016
i-C5 0.003 72.151 490.4 828.63 2.48589 1.4712
n-C5 0.008 72.151 488.6 848.8 6.7904 3.9088
C6 0.001 86.178 436.9 913.60 0.9136 0.4369
C7 0.001 100.205 398.8 972.7 0.9727 0.3988
N2 0.050 28.013 493.1 227.49 11.3745 24.655
CO2 0.030 44.010 1071 547.91 16.4373 32.13
H2S 0.020 34.076 1300 672.45 13.449 26
( Tci ) ( YiTci ) ( YiPci )ComponentMole Fraction (
Yi )
Apparent Molecular
Weight ( Mi )( Pci )
KIMIA FISIKA HIDROCARBON
1. For the gas composition given in the following text, determine apparent molecular weight, spesific
gravity, pseudo-critical pressure, pseudo critical temperature of gas
ComponentMole Fraction (
Yi )
Apparent Molecular
Weight ( Mi )( YiMi )
= 29 = 20.70268
29 = 0.713886
= 1 = 643.242 = 20.70268
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Known :
Answer :
2. After you determine Ppc and Tpc, Determine Pseudo-Reduce Pressure and Pseudo-ReduceTemperature . After that find gas compressibility Factor using Standing Kartz Correlation and Beggs
Brill Correlation. ( Standing Kartz Chart is attached )
= 384.07288° = 681.3052
= 384.07288 ° = 681.3052
= 213℉+ 460 = 673° = 3250 = 384.07288 ° = 681.3052
= = 3250
681.3052= 4.77
= = 673°
384.07288°= 1.75
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Beggs Brill Correlation
= 1.39( − 0.92).−0.36 − 0.10= 1.39(1.75− 0.92).−0.36 1.75 −0.10
= 1.39(0.83).
−0.63−0.10= 1.39 0.911043358 −0.63−0.10= 1.266350268− 0,63− 0.10= 0.536350268
= 0.62− 0.23 + 0.066 − 0.86−0.037 + 0.32
10
= 9( − 1)= 9(1.75 − 1)= 9(0.75)= 6.75
= 0.62−0.23(1.75) 4.77+ 0.0661.75−0.86 −0.037 4.77 + 0.32(4.77)
10.
= 0.62−0.23(1.75) 4.77+ 0.0661.75−0.86 −0.037 4.77 + 0.32(4.77)
10.
= 1.037475 + 0.845436408+ 0.000670286= 1.883581694
= 0.132 − 0.32 = 0.132− 0.32 1.75= 0.132− 0.32 0.243038049= 0.132− 0.077772176= 0.054227824
= 0.3106− 0.49 + 0.1824
= 0.3106− 0.49 1.75 + 0.1824 1.75
= 0.3106− 0.8575+ 0.5586= 0.0117
= 10
= 10.
= 1.027306415
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= + 1 − +
= 0.536350268+ 1−0.5363502682.718. +0.054227824(4.77)
= 0.536350268+ 0.070762154+ 0.25866672= 0.865779142= 0.87
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