Transcript
  • 8/10/2019 Contoh Hitungan Poligon Tertutup

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    awal = 126

    Titik f

    .' ." (Derajat) "

    A 89 18 0 -740070

    B 89 36 14.4 123345 89

    C 89 9 46.8 123345 89

    D 80 21 54 123345 80

    E 255 17 34.8 123345 255

    0

    F 94 20 45.6 123345 94

    513 83 150 616725 607

    360 0 20

    = N = 6

    f = - (N-2)*180 = -205.575 Derajat = -740070 detik

    = - f / N = 123345 detik

    514.425

  • 8/10/2019 Contoh Hitungan Poligon Tertutup

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  • 8/10/2019 Contoh Hitungan Poligon Tertutup

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    d sin d cos fx fy x

    (m) (m) (m) (m) (m)

    132.4198 106.0864138.6814 (102.0799) (46.1024)

    82.3574 29.6142 (23.4313)

    22.1348 91.1612 (25.1153)

    (110.7539) 87.3908 (37.7707)

    145.7638 91.6829 (46.1024)

    9.8155 86.9679 #DIV/0!

    132.4198 106.0864 132.4198 106.0864 (132.4198)

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    y X Y

    (m) (m) (m)

    100.000 50.000(36.9343)

    192.579 (89.014)

    (18.7717)

    251.505 (78.172)

    (20.1208)

    248.525 (7.131)

    (30.2595)

    100.0000 50.0000

    (36.9343)

    199.6615 104.7486#DIV/0!

    (106.0864)


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